【js】获取url query参数的方法 Jelly Orange 2017-08-06 JS JS, url参数 1234567891011const getUrlParams = (url) => { let str = url.split('?')[1] let items = str.split('&') let result = {}; let arr = []; for (let i = 0; i < items.length; i++) { arr = items[i].split('='); result[arr[0]] = arr[1]; } return result}